Can someone show me how to work this please.?

A long-distance runner runs 3 miles south and then 7 miles east. How far is the runner from the starting point?

Can someone show me how to work this please.

3 Answers

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  • bcdas
    Lv 4
    1 decade ago
    Favorite Answer

    use the formula for a right triangle a^2 + b^2 = c^2

    3^2 + 7^2 =58 = c^2

    c = sqrt(58)

    Source(s): in calc3
  • 1 decade ago

    When you think of this, it is a triangle. 3 would be the base, and 7 would be the height, you could use sin, cos, or tan, or you could just use Pythagorean Theorem to find the hypotenuse, which is how far the person ran.

    I will use the Pythagorean Theorem

    a² + b² = c²

    3² + 7² = 58

    √58 =7.615773106

    Round that and you get 7.6

  • ?
    Lv 5
    1 decade ago

    Right triangle problem:

    3^2 + 7^2 = c^2

    9 + 49 = c^2

    c^2 = 58

    c = sqrt.58

    runner is sqrt.58 miles from starting point

    If you want, take the sqrt. of 58 and round to desired # of dec. places

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