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# Can someone show me how to work this please.?

A long-distance runner runs 3 miles south and then 7 miles east. How far is the runner from the starting point?

Can someone show me how to work this please.

### 3 Answers

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- bcdasLv 41 decade agoFavorite Answer
use the formula for a right triangle a^2 + b^2 = c^2

3^2 + 7^2 =58 = c^2

c = sqrt(58)

Source(s): in calc3 - 1 decade ago
When you think of this, it is a triangle. 3 would be the base, and 7 would be the height, you could use sin, cos, or tan, or you could just use Pythagorean Theorem to find the hypotenuse, which is how far the person ran.

I will use the Pythagorean Theorem

a² + b² = c²

3² + 7² = 58

√58 =7.615773106

Round that and you get 7.6

- ?Lv 51 decade ago
Right triangle problem:

3^2 + 7^2 = c^2

9 + 49 = c^2

c^2 = 58

c = sqrt.58

runner is sqrt.58 miles from starting point

If you want, take the sqrt. of 58 and round to desired # of dec. places

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