Can someone show me how to work this please.?
A long-distance runner runs 3 miles south and then 7 miles east. How far is the runner from the starting point?
Can someone show me how to work this please.
- bcdasLv 41 decade agoFavorite Answer
use the formula for a right triangle a^2 + b^2 = c^2
3^2 + 7^2 =58 = c^2
c = sqrt(58)Source(s): in calc3
- 1 decade ago
When you think of this, it is a triangle. 3 would be the base, and 7 would be the height, you could use sin, cos, or tan, or you could just use Pythagorean Theorem to find the hypotenuse, which is how far the person ran.
I will use the Pythagorean Theorem
a² + b² = c²
3² + 7² = 58
Round that and you get 7.6
- ?Lv 51 decade ago
Right triangle problem:
3^2 + 7^2 = c^2
9 + 49 = c^2
c^2 = 58
c = sqrt.58
runner is sqrt.58 miles from starting point
If you want, take the sqrt. of 58 and round to desired # of dec. places