solve for R C=K(Rr/R-r)?

solve for R C+K(Rr/R-r)

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  • 1 decade ago
    Favorite Answer

    C=K(Rr/R-r)

    Divide both sides by K:

    C/K = (Rr/R-r)

    Multiply both sides by (R-r):

    (R-r)(C/K) = Rr

    Distribute C/K:

    CR/K-Cr/K = Rr

    Subtract Rr from both sides, add Cr/K to both sides:

    CR/K - Rr = Cr/K

    Extract R:

    R(C/K - r) = Cr/K

    Divide both sides by (C/K - r):

    R = (Cr/K)/(C/K - r)

    Since K/K = 1, we can make r = Kr/K in order to give it a common denominator with C/K:

    R = (Cr/K)/(C/K - Kr/K)

    R = (Cr/K)/((C - Kr)/K)

    Dividing by a fraction is the same as multiplying by the reciprocal:

    R = (Cr/K)(K/(C-Kr))

    R = Cr/(C-Kr)

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  • Anonymous
    1 decade ago

    R C=K(Rr/R-r)

    (R C)/(Rr/R-r)=K

    (R C)/(Rr/R-r)K=K/K

    (R C)/(Rr/R-r)K=1

    -1+ (R C)/(Rr/R-r)K=1 -1

    0 . (R C)/(Rr/R-r)K=0 . 0

    0 = 0

    as 0 equals 0, that the answer is true

    PS: you are lost.

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  • 3 years ago

    a million / R = a million / A + a million/ B + a million/C = (B + A) / (AB) + a million/ C (uncomplicated denominator then upload) = (C(B + A) + AB) / CAB (comparable element back) take reciprocal of the two facets (turn): R = (C*A*B) / (CB +CA + AB) Please no longer that the R = A + B + C answer is incorrect for the reason which you could no longer take the reciprocal of all 3 fractions, first you could desire to upload them mutually.

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  • 1 decade ago

    R C=K(Rr/R-r)=

    ktc k ktc c ... r

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