# What was the speed of the current and the speed of the boat in still water?

It took an hour for Rolando in a boat to go six miles upstream. With the same path, it took him 45 minutes to return.

Relevance

b = speed of boat; c = speed of current

6/(b - c) = 1

b - c = 6

b = c + 6

6/(b + c) = 3/4

8/(b + c) = 1

b + c = 8

b = 8 - c

Speed of current—c:

c + 6 = 8 - c

2c = 2

c = 1

Speed of boat:

= 1 + 6

= 7

Answer: speed of current, 1 mph; speed of boat, 7 mph

Sigfred

It took an hour for Rolando in a boat to go six miles upstream. With the same path, it took him 45 minutes to return

What was the speed of the current and the speed of the boat in still water?

solution:

Let RB = Rate of Boat m/min

CR = Current Rate

Rate = distance / time

Distance = 6 miles

Up stream:

RB - CR = 6 /60 <- eq 1

Down Stream:

RB + CR = 6 /45 <- eq 2

Add eq 1 & eq 2

2RB = 6 /60 + 6 /45

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Rate of Boat at still water

RB = 0.117 mile/min ◄ Ans

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Substitute RB to eq 1

RB - CR = 6 /60 <- eq 1

0.117 - CR = 0.1

CR = 0.117 - 0.1

===============================

The water current

CR = 0.017 mile/min ◄ Ans

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hope this helps

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• Anonymous

x = boat's speed

y = current's speed

distance/time(up)

6/1 = 6

distance/time(down)

6/(3/4 hr)= 8

x - y = 6

x + y = 8

x = 7 mph

y = 1 mph