? asked in Science & MathematicsMathematics · 1 decade ago

What was the speed of the current and the speed of the boat in still water?

It took an hour for Rolando in a boat to go six miles upstream. With the same path, it took him 45 minutes to return.

3 Answers

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  • 1 decade ago
    Favorite Answer

    b = speed of boat; c = speed of current

    6/(b - c) = 1

    b - c = 6

    b = c + 6

    6/(b + c) = 3/4

    8/(b + c) = 1

    b + c = 8

    b = 8 - c

    Speed of current—c:

    c + 6 = 8 - c

    2c = 2

    c = 1

    Speed of boat:

    = 1 + 6

    = 7

    Answer: speed of current, 1 mph; speed of boat, 7 mph

  • 1 decade ago

    Sigfred

    It took an hour for Rolando in a boat to go six miles upstream. With the same path, it took him 45 minutes to return

    What was the speed of the current and the speed of the boat in still water?

    solution:

    Let RB = Rate of Boat m/min

    CR = Current Rate

    Rate = distance / time

    Distance = 6 miles

    Up stream:

    RB - CR = 6 /60 <- eq 1

    Down Stream:

    RB + CR = 6 /45 <- eq 2

    Add eq 1 & eq 2

    2RB = 6 /60 + 6 /45

    ===============================

    Rate of Boat at still water

    RB = 0.117 mile/min ◄ Ans

    ===============================

    Substitute RB to eq 1

    RB - CR = 6 /60 <- eq 1

    0.117 - CR = 0.1

    CR = 0.117 - 0.1

    ===============================

    The water current

    CR = 0.017 mile/min ◄ Ans

    ===============================

    hope this helps

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    God Bless

    Lim ♥ E

  • Anonymous
    1 decade ago

    x = boat's speed

    y = current's speed

    distance/time(up)

    6/1 = 6

    distance/time(down)

    6/(3/4 hr)= 8

    x - y = 6

    x + y = 8

    x = 7 mph

    y = 1 mph

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