How many grams of O2 are needed to burn 1.80 g of C8H18?

Given the following:

2 C8H18(l) + 25 O2(g) 16 CO2(g) + 18 H2O(l)

How many grams of O2 are needed to burn 1.80 g of C8H18?

Please show work :)
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