? asked in Science & MathematicsMathematics · 1 decade ago

What is the point of intersection for 2x+3y=0, 2x-3y=0?

2x+3y=0

2x-3y=0?

7 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    2x+3y=0

    3y = -2x

    y = -2x/3

    Plug that into the second equation: 2x-3y=0 when y = -2x/3

    2x-3y = 0

    2x-3(-2x/3) = 0

    2x + 6x/3 = 0

    6x/3 + 6x/3 = 0

    12x/3 = 0

    x = 0

    They intersect when x=0

    2(0)+3y = 0

    3y = 0

    y = 0

    They intersect at (0,0)

  • Anonymous
    1 decade ago

    -2x-3y= 0

    2x-3y =0

    0-3y = 0

    3 3

    y = 0

    2x - 0 = 0

    +0 0

    2x = 0

    2 2

    answer is (0,0)

    Source(s): did it right now
  • 1 decade ago

    2x + 3y = 0

    2x - 3y = 0

    2x + 3y = 0

    2x - 3y = 0

    ------------------

    4x = 0

    x = 0

    2(0) + 3y = 0

    0 + 3y = 0

    3y = 0

    y = 0

    (0, 0)

  • Anonymous
    1 decade ago

    ✐Derivation✐

    Use addition method.

    4x = 0

    x = 0

    2(0) + 3y = 0

    3y = 0

    y = 0

    (0,0)

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  • Anonymous
    1 decade ago

    you should be able to figure it out "from inspection" (i.e. you don't need to do any written work).

    if you add the equations, that immediately gives x=0.

    substituting this into either equation immediately gives y=0.

    so the point of intersection is the origin.

  • 1 decade ago

    x=0

    y=0

  • Anonymous
    1 decade ago

    oh my looorrrd do your own homework.

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