What is the point of intersection for 2x+3y=0, 2x-3y=0?

Question

2x+3y=0

2x-3y=0?

Answer 1

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2x+3y=0

3y = -2x

y = -2x/3

Plug that into the second equation: 2x-3y=0 when y = -2x/3

2x-3y = 0

2x-3(-2x/3) = 0

2x + 6x/3 = 0

6x/3 + 6x/3 = 0

12x/3 = 0

x = 0

They intersect when x=0

2(0)+3y = 0

3y = 0

y = 0

They intersect at (0,0)

Answer 2

-2x-3y= 0

2x-3y =0

0-3y = 0

3 3

y = 0

2x - 0 = 0

+0 0

2x = 0

2 2

answer is (0,0)

Source(s): did it right now

Answer 3

2x + 3y = 0

2x - 3y = 0

2x + 3y = 0

2x - 3y = 0

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4x = 0

x = 0

2(0) + 3y = 0

0 + 3y = 0

3y = 0

y = 0

(0, 0)

Answer 4

✐Derivation✐

Use addition method.

4x = 0

x = 0

2(0) + 3y = 0

3y = 0

y = 0

(0,0)

Answer 5

you should be able to figure it out "from inspection" (i.e. you don't need to do any written work).

if you add the equations, that immediately gives x=0.

substituting this into either equation immediately gives y=0.

so the point of intersection is the origin.

Answer 6

x=0

y=0

Answer 7

oh my looorrrd do your own homework.