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Simplify 2ln(e^3) / [ln(1) - ln(e)]?
nuff said
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- 1 decade ago
Move the 2 in 2ln(e^3) to inside the brackets to make ln (e ^ 6).
Combine the two terms in ln 1 - ln e, which becomes ln (1/e)
Because ln e = 1, and ln(e^6) can be expressed in 6(ln e), then the numerator = 6.
The denominator can expressed as ln (e^ -1), which equals -ln e, which equals -1.
Therefore, 6/ -1 = -6, and thats ur answer.
Hope it helps
- 1 decade ago
In e =1
In e^3 =3
In (1) = 0
In (-e) = -In (e) = -1
So 2In e^3 /(In(1)-In(e)) = 6/(0-1) = -6
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