What is (a-b)^2-16(a+2b)^2 fully factored?
I have a math test 2morrow, and I want 2 make sure I know everything.
An explanation would be nice. PLEEZ
10 points for the first answer.
- Roger the MoleLv 71 decade agoFavorite Answer
What you've got is the difference of squares, where 16(a+2b)^2 = [4(a+2b)]^2
[(a-b) + 4(a+2b)] [(a-b) - 4(a+2b)]
The factoring is finished here, but it would be nice to simplify:
(-3)(5a + 7b) (a + 3b)