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# What is (a-b)^2-16(a+2b)^2 fully factored?

I have a math test 2morrow, and I want 2 make sure I know everything.

Update:

An explanation would be nice. PLEEZ

Update 2:

10 points for the first answer.

### 1 Answer

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- Roger the MoleLv 71 decade agoFavorite Answer
What you've got is the difference of squares, where 16(a+2b)^2 = [4(a+2b)]^2

So

(a-b)^2-16(a+2b)^2 =

[(a-b) + 4(a+2b)] [(a-b) - 4(a+2b)]

The factoring is finished here, but it would be nice to simplify:

(-3)(5a + 7b) (a + 3b)

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