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# Brain teaser/ logic homework?

I don't understand these problems hopefully you the answerer can guide me through the explanation and answers:

1. I subsribe to the comic-of-the-month club. Each month I can buy any number of the 48 titles offered by the club. The first month I bought five comics for $3.07. The second month I bought two comics for $1.72. The next month I bought six of the club offerings for $3.52. In May I bought three more for a charge of $2.17. The club charges a handling fee and then a fee for each comic. How much would it have cost to buy all 48 titles at the same time?

### 2 Answers

- chauncyLv 71 decade agoFavorite Answer
The question doesn't say whether all comics cost the same. Assuming they do, let the cost of a comic = c and the handling fee = h.

Then we can find h and c by solving simultaneously the equations for any 2 transactions. I'll use the first two:

h + 5c = $3.07

h + 2c = $1.72

Subtracting the second equation from the first, we get

3c = $1.35

c = 45 cents

and h = $1.72 - 2c = $1.72 - 90 cents = 82 cents.

(I note that

h + 6c = 82 cents + (6 x 45) cents = $3.52 and

h + 3c = 82 cents + (3 x 45) cents = $2.17,

so evidently the comics are indeed all the same price.)

The cost of buying 48 titles at once =

82 cents + (48 x 45) cents

= 82 cents + $21.60

= $22.42