# What is the range of a 10 bit binary number?

What is the maximum?

What is the minimum?

Please explain so I can understand

### 5 Answers

- 1 decade agoFavorite Answer
for 10 bit binary number

maximum=1023

minimum=0

for n bit binary number

range: 0 to 2^n-1 (total combination= 2^n)

for example: n=3

range: 0 to 7 (i.e. 2^3-1)

while total combination=2^3=8

000=0

001=1

010=2

011=3

100=4

101=5

110=6

111=7

- Anonymous1 decade ago
That depends on how the number is stored. If it's an unsigned integer, it will be 1024 (0 - 1023) Twos complement notation will have the same range but different min (-512) and max (511)

If the number is in floating point notation, the range is no longer meaningful, but the precision is the key measurement.

Source(s): Computer Science teacher and author http://www.aharrisbooks.net - gene_frequencyLv 71 decade ago
All correct answers so far, just wanted to share how you can get a qwk answer with most any calculator.

The answer is 2 to the power of 10, which yields 1024 (so, 0 - 1023 ....if unsigned integer)

In notation that's 2^10 ... use your windows calculator...use 'View' > 'Scientific'. Look for the x^y key....

Enter '2', then hit x^y key, enter 10, click '=' ...you're there.

What is the range for a sixteen bit int? 2^16 =65536...so, it is 0 thru 65535.

How bout 32 bit? Easy now, right? :-) cheers...

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