Anonymous

# factors of 112 and 432 please?

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- John FLv 71 decade agoBest Answer
prime factors of 112 = 2 * 2 * 2 * 2 * 7 = 2⁴ * 7

prime factors of 432 = 2 * 2 * 2 * 2 * 3 * 3 * 3 = 2⁴ * 3³

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all factors of 112 = k (112) with k ∈ ℤ

all factors of 432 = k (432) with k ∈ ℤ

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- plays_poorly...Lv 71 decade ago
112 ---2 x 56 = 2 x 8 x 7 = 2x2x2x2x7

432 = 4 x 108 = 4 x 4 x17 = 2x2x2x2x17

- Anonymous1 decade ago
✐Derivation✐

"Break" those numbers into simple prime factors!!!

112 = 2*2*2*2*7

432 = 2*2*3*3*3

- Anonymous1 decade ago
the answer is 27

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