Find the intercepts pf the following linear equation. x - 8y - 16 = 0?

x-intercept

(x,y) = ( ? , ? )

y-intercept

(x,y) = ( ? , ? )

6 Answers

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  • 1 decade ago
    Best Answer

    Hi,

    For this question, recall that the x-intercept occurs when y = 0 and therefore we get:

    x - 8(0) - 16 = 0

    x = 16 or (16,0) = x-intercept

    Now, the y-intercept occurs when x = 0 and therefore we get:

    0 - 8y - 16 = 0

    -8y = 16

    y = -2 or (0,-2) = y-intercept

    I hope that helps you out! Please let me know if you have any other questions!

    Source(s): College Calculus Student ; Math Tutor
  • 1 decade ago

    x - 8y - 16 = 0

    -8y = -x + 16

    y = (1/8)x - 2

    x intercept is (16,0)

    y intercept is (0,-2)

    To get x-intercept, plug in 0 for y.

    To get y-intercept, plug in 0 for x.

  • Anonymous
    1 decade ago

    x - 8y - 16 = 0

    x = 8y + 16

    When x = 0, y= -2

    x - 16 = 8y

    (x-16)/8 = y

    When y = 0, x = 16

    x-intercept: (16, 0)

    y-intercept: (0, -2)

  • Anonymous
    1 decade ago

    y intercept is ( 0 , -2 )

    x intercept is ( 16 , 0 )

    Source(s): mind
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  • DOVE
    Lv 6
    1 decade ago

    x - 8y - 16 = 0

    y intercept is given by value of y

    When x=0

    8y= x-16

    8y= -16

    y=-2

    x intercept is given by value of x when y=0

    x=16

  • 1 decade ago

    For x=0 we get y=-2

    For y=0 we get x=16

    The intercepts are:

    (0, -2) and (16, 0)

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