# Find the intercepts pf the following linear equation. x - 8y - 16 = 0?

x-intercept

(x,y) = ( ? , ? )

y-intercept

(x,y) = ( ? , ? )

### 6 Answers

- The VC 06Lv 71 decade agoBest Answer
Hi,

For this question, recall that the x-intercept occurs when y = 0 and therefore we get:

x - 8(0) - 16 = 0

x = 16 or (16,0) = x-intercept

Now, the y-intercept occurs when x = 0 and therefore we get:

0 - 8y - 16 = 0

-8y = 16

y = -2 or (0,-2) = y-intercept

I hope that helps you out! Please let me know if you have any other questions!

Source(s): College Calculus Student ; Math Tutor - 1 decade ago
x - 8y - 16 = 0

-8y = -x + 16

y = (1/8)x - 2

x intercept is (16,0)

y intercept is (0,-2)

To get x-intercept, plug in 0 for y.

To get y-intercept, plug in 0 for x.

- Anonymous1 decade ago
x - 8y - 16 = 0

x = 8y + 16

When x = 0, y= -2

x - 16 = 8y

(x-16)/8 = y

When y = 0, x = 16

x-intercept: (16, 0)

y-intercept: (0, -2)

- Anonymous1 decade ago
y intercept is ( 0 , -2 )

x intercept is ( 16 , 0 )

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- DOVELv 61 decade ago
x - 8y - 16 = 0

y intercept is given by value of y

When x=0

8y= x-16

8y= -16

y=-2

x intercept is given by value of x when y=0

x=16