Find the intercepts pf the following linear equation. 2x - y = 2?

x-intercept

(x,y) = ( , )

y-intercept

(x,y) = ( , )

3 Answers

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  • 1 decade ago
    Favorite Answer

    Hi,

    Recall that the x-intercept occurs when 'y' equals zero to get:

    2x - 0 = 2

    2x = 2

    x = 1 or (1,0)

    Also, the y-intercept occurs when 'x' equals zero and therefore we get:

    2(0) - y = 2

    -y = 2

    y = -2 or (0,-2)

    I hope that helps you out! Please let me know if you have any other questions!

    Source(s): College Calculus Student ; Math Tutor
  • 1 decade ago

    For x-intercept, sub y=0

    2x - 0 = 2

    2x = 2

    x = 1

    So point of x-intercept is (1,0)

    For y-intercept, sub x = 0

    2.0 - y = 2

    -y = 2

    y = -2

    So point of y-intercept is (0, -2)

  • 1 decade ago

    x- (1,0)

    y- (0,-2)

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