Charges and Electrons: Help Please?
Suppose that 0.63 g of hydrogen is separated into electrons and protons. Suppose also that the protons are placed at the Earth’s North PoleandtheelectronsareplacedattheSouth Pole.
The Coulomb constant is 8.98755 × 10^9N· m^2/C^2
and Avogadro’s number is 6.02214× 10^23mol^-1. What is the resulting compressional force on Earth? The radius of the Earth is 6.37× 10^6m. Answer in units of N.
What a diffucult qs, please help.
- Bandagadde SLv 61 decade agoFavorite Answer
No.of atoms in 0.63 g of hydrogen =0.63x6.02214x10^23
This is also equal to no. of protons and electrons.
Force between them is
= 8.16x10^5 N
- JacyLv 71 decade ago
= 1.88x10^23 atoms
Therefore the # of protons is equal to 1.88x10^23
The Coulomb electrostatic force is given by:
F = kN²e²/(2r)², where N is the # of protons and
2r is the distance between earths' north/south poles
F = (8.98755x10^9)(1.88x10^23)²(1.6x10^-19)² /
F = 0.5x10^5 N
- 1 decade ago
1st u find the no of h atoms in .63g
for that 0.63/(6.02214x10^23)
results gives no of h atom
then you coulomb's law of force.