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A 41 kg sample of water absorbs 327 kJ of heat.If the water was initially at 20.2,C what is its final temperature?

Calculate the amount of heat required to raise the temperature of a 36 sample of water from 9 g to 27 g.

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- Anonymous1 decade agoFavorite Answer
Specific heat capacity of water is 4.1855 J/g C= 4.1855 kJ/kg C

Therefore the answer to question one is 327 kJ / 4.1855 kJ/kg C /41 kg = 1.9 C. Add this to the initial temperature 20.2 C + 1.9 C= 22.1 C

The second question is nonsensical. "Raise the temperature of a 36 sample of water from 9 g to 27 g". 36 what? 9g to 27g??

- 1 decade ago
E=m C delta T ( T2-T1) substitute everything make sure u have SI units and solve for T2.

I am not sure what the sec question asks , can u clarify?

Source(s): Chem major

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