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# math question help!!! A resort hotel in Cancun offers vacationers two diving adventure plans.?

Plan A gives 3 nights' lodging and 5 dives. Plan B gives 5 nights' lodging and 6 dives.

Suppose the resort posts a price list in which plan A costs $700 and plan B costs $950. What prices are being assumed per night and per dive? Please show ur calculations.

that wasnt exactly what i was looking for but it helped me solve the problem on my own.. thanks anyway!

oooo nevermind i guess my computer didnt show all that lol i just did all that on my own. thank you!

### 2 Answers

- 1 decade agoFavorite Answer
Plan A: 3x + 5y = 700

Plan B: 5x + 6y = 950

5(3x + 5y) = 700(5)

3(5x + 6y) = 950(3)

15x + 25y = 3500

-(15x + 18y = 2850)

--------------------------

7y = 550

y = 650/7 or 92.86

3x + 5y = 700

3x + 5(650/7) = 700

3x = 700 - 3250/7

3x = (4900 - 3250)/7

x = 1650/21 or 78.57

cost per night = $ 78.57

cost per dive = $ 92.86

- 1 decade ago
1 Night's Lodging = $42.86

1 Dive = $114.29

Here are the given equations

3x + 5y = 700

5x + 6y = 900

Multiple the first equation by -5 in order to add them together and cancel out the X from the equations.

-15x – 25y = -3500

15x + 18y = 2700

Next, solve for Y

-7y = -800

Y = 114.29

Plug Y back into the original equation to find X

3x + 5(114.29) = 700

X= 42.86