math question help!!! A resort hotel in Cancun offers vacationers two diving adventure plans.?

Plan A gives 3 nights' lodging and 5 dives. Plan B gives 5 nights' lodging and 6 dives.

Suppose the resort posts a price list in which plan A costs $700 and plan B costs $950. What prices are being assumed per night and per dive? Please show ur calculations.

Update:

that wasnt exactly what i was looking for but it helped me solve the problem on my own.. thanks anyway!

Update 2:

oooo nevermind i guess my computer didnt show all that lol i just did all that on my own. thank you!

2 Answers

Relevance
  • 1 decade ago
    Favorite Answer

    Plan A: 3x + 5y = 700

    Plan B: 5x + 6y = 950

    5(3x + 5y) = 700(5)

    3(5x + 6y) = 950(3)

    15x + 25y = 3500

    -(15x + 18y = 2850)

    --------------------------

    7y = 550

    y = 650/7 or 92.86

    3x + 5y = 700

    3x + 5(650/7) = 700

    3x = 700 - 3250/7

    3x = (4900 - 3250)/7

    x = 1650/21 or 78.57

    cost per night = $ 78.57

    cost per dive = $ 92.86

  • 1 decade ago

    1 Night's Lodging = $42.86

    1 Dive = $114.29

    Here are the given equations

    3x + 5y = 700

    5x + 6y = 900

    Multiple the first equation by -5 in order to add them together and cancel out the X from the equations.

    -15x – 25y = -3500

    15x + 18y = 2700

    Next, solve for Y

    -7y = -800

    Y = 114.29

    Plug Y back into the original equation to find X

    3x + 5(114.29) = 700

    X= 42.86

Still have questions? Get your answers by asking now.