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# can some one help me with this math?

4x^2 + 25 = 20x

3/4p = 4/5p + 1/2

x/x-6 + 7 = 6/x-6

x^2 - 16x + 128 = 0

9x - (4x + 7) = 2x - 31

x^2 -4x = 0

x^2 - 2x - 14 = 0

Thanks any help will be appreciated im confused on this

### 2 Answers

- Anonymous1 decade agoFavorite Answer
for all of these problems you want the equation to be set to 0, for a couple of them there already are. you'll have to do some re-arranging so it ends up that way. for example, the first one you subtract 20 from both sides so you have 4x^2 -20x +25=0.

You weren't clearn on what you wanted us to do but i'm assuming solve for the x's. There are 2 ways to do this, you can factor, or you can use the quadratic formula. You'll need an a, b , and c to do use this formula which corresponds to the example i gave you of 4x^2 -20x +25. a=4, -20 = b, 25= c. The formula would be -b = -+ sqrt(b^2-4ac / 2a) . I assume you've learned this formula, it looks a bit confusing on here but the -+ means plus or minus, the negative sign goes on the plus sign. sqrt= square root. square root of b^2 -4ac goes in the numerator and the 2a goes in the denominator, solve from there to get your x values. Now on the other hand, if you're able to factor, it is a lot more simple this way. for example with x^2-4x=0 would take a common factor out which is x. This would give you x(x-4)=0. Now you set x =0 and x-4=0. So x =0 or x=4. I didn't want to give you the answers because that'd be cheating so e-mail me if you want after you complete the questions and I'll check them over for you if you like.

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