? asked in Science & MathematicsMathematics · 1 decade ago

K=(dy/dx)/ (1+(dy/dx)^2)^1/2?

Can anyone help me to integrate this equation

Update:

K is constant.

I'm trying to find just the integration

2 Answers

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  • 1 decade ago
    Favorite Answer

    K^2[1 + (dy/dx)^2] = (dy/dx)^2

    (dy/dx)^2 (K^2 - 1) = -K^2

    dy/dx = K/√(1-K^2)

    thus

    y = Kx/√(1-K^2) + C

  • Anonymous
    1 decade ago

    Is K supposed to be some other function of x? Are you trying to solve this differential equation for y? Or are you just trying to find the integral of y' / (1 + y' ^2)^(1/2) ?

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