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# K=(dy/dx)/ (1+(dy/dx)^2)^1/2?

Can anyone help me to integrate this equation

Update:

K is constant.

I'm trying to find just the integration

### 2 Answers

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- Alam Ko IyanLv 71 decade agoFavorite Answer
K^2[1 + (dy/dx)^2] = (dy/dx)^2

(dy/dx)^2 (K^2 - 1) = -K^2

dy/dx = K/√(1-K^2)

thus

y = Kx/√(1-K^2) + C

- Anonymous1 decade ago
Is K supposed to be some other function of x? Are you trying to solve this differential equation for y? Or are you just trying to find the integral of y' / (1 + y' ^2)^(1/2) ?

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