5x-6y=19, 6x+5y=-30 are these parallel or perpendicular or neither?

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5x-6y=19
-6y = -5x+19
y = (5/6)x-(19/6)
Since this line is expressed in the standard linear form of y=mx+b where m is the slope, so the slope of this line = m1= 5/6

6x+5y=-30
5y = -6x+30
y = (-6/5)x+6
Similarily, since this line is expressed in the standard linear form of y=mx+b where m is the slope, so the slope of this line = m2= -6/5

Since m1*m2 = (5/6)*(-6/5) = -1,then these two lines are perpendicular to each other.
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  • kyle h answered 5 years ago
    5x-6y=19, 6x+5y=-30

    -6y=-5x+19, 5y=-6x-30
    y=(5/6)x-(19/6), y=(-6/5)x-6

    Parallel is same slope, perpendicular is opposite reciprocals. Perpendicular?
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  • Hemant answered 5 years ago
    Slope of line ax+by+c=0 is = -a/b.

    Slope of first line is m1 = 5/6

    Slope of second line is m2 = - 6/5.

    Their product is m1x m2 = -1.

    So lines are PERPENDICULAR...............Ans.
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  • MyEyeHurts :( answered 5 years ago
    Dont you have the equtations to figure these out?
    M= (x+x, y+y) Divided by two.
    Slope = Rise over run
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  • babuprincess99 answered 5 years ago
    perpendicular.

    5x-6y=19
    -6y=-5x+19
    y= (5/6)x +19

    m = 5/6

    6x+5y=-30
    5y=-6x-30
    y=(-6/5)x -30

    m=-6/5

    5/6 & -6/5 are negative reciprocals therefore the lines are perpendicular
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  • яα¢нαєℓ answered 5 years ago
    Perpendicular. The slopes are reciprocals of each other. -A/B = 5/6 and -6/5
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