# 5x-6y=19, 6x+5y=-30 are these parallel or perpendicular or neither?

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Best Answer

5x-6y=19

-6y = -5x+19

y = (5/6)x-(19/6)

Since this line is expressed in the standard linear form of y=mx+b where m is the slope, so the slope of this line = m1= 5/6

6x+5y=-30

5y = -6x+30

y = (-6/5)x+6

Similarily, since this line is expressed in the standard linear form of y=mx+b where m is the slope, so the slope of this line = m2= -6/5

Since m1*m2 = (5/6)*(-6/5) = -1,then these two lines are perpendicular to each other.

-6y = -5x+19

y = (5/6)x-(19/6)

Since this line is expressed in the standard linear form of y=mx+b where m is the slope, so the slope of this line = m1= 5/6

6x+5y=-30

5y = -6x+30

y = (-6/5)x+6

Similarily, since this line is expressed in the standard linear form of y=mx+b where m is the slope, so the slope of this line = m2= -6/5

Since m1*m2 = (5/6)*(-6/5) = -1,then these two lines are perpendicular to each other.

### Other Answers (5)

Rated Highest-
5x-6y=19, 6x+5y=-30

-6y=-5x+19, 5y=-6x-30

y=(5/6)x-(19/6), y=(-6/5)x-6

Parallel is same slope, perpendicular is opposite reciprocals. Perpendicular? -
Slope of line ax+by+c=0 is = -a/b.

Slope of first line is m1 = 5/6

Slope of second line is m2 = - 6/5.

Their product is m1x m2 = -1.

So lines are PERPENDICULAR...............Ans. -
Dont you have the equtations to figure these out?

M= (x+x, y+y) Divided by two.

Slope = Rise over run -
perpendicular.

5x-6y=19

-6y=-5x+19

y= (5/6)x +19

m = 5/6

6x+5y=-30

5y=-6x-30

y=(-6/5)x -30

m=-6/5

5/6 & -6/5 are negative reciprocals therefore the lines are perpendicular -
Perpendicular. The slopes are reciprocals of each other. -A/B = 5/6 and -6/5

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