Calculus max value of q(r)?

What is the maximum value of q(r) = r3 + 7r2 - 24r + 6 for r∈[-8, -1]?

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  • Anonymous
    1 decade ago
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    q(r) = r³ + 7r² - 24r + 6

    q'(r) = 3r² + 14r - 24

    extreme value if q'(r) = 3r² + 14r - 24 = 0

    r = -6

    r = 4/3

    q(-6) = 186

    q(-8) = 134

    q(-1) = 36

    conclusion, for r∈[-8, -1], q_max = 186

  • 1 decade ago

    Did you mean r^3 +7*r^2-24*r+6 ?

    The value can reach reach maximum when differential is 0.

    Differnential is 3*r^2+14*r-24.

    Now 3*r^2+14*r-24=0 I hope you can solve it. then see which solution is in range r∈[-8, -1].

  • 1 decade ago

    x=-6, derive it set equal to 0

  • 1 decade ago

    poop

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