# standard temperature ideal gas questions?

can anyone help me, I have no idea what to do in this situation.

the pressure on 600cm3 of gas is increased from 100kpa to 300kpa at constant temperature. What will the new volume of gas be?

I know I have to use the equation Pinitial x V initial/T initial = P final x v final/ T final.

but I don't know what the standard temperature is!!

how do you find it?

Relevance

600x100=300xV

V=200cm3

it doesn't matter what the standard temperature is since it is the same on both sides and hence cancels out :-)

Source(s): maths
• The standard temperature is 273 K

convert 100kpa and 300kpa to atm

1atm=10^3 Pa

Convert 600cm^3 to Liters

1 cm^3 = 0.001 L

substitute all the values to your equation.

• Standard temperature is 20 °C (293.15 K, 68 °F) and an absolute pressure of 101.325 kPa.

So: 20 °C and 100 kPa.

Hope this helps. :)

• undergo in concepts that P1V1/T1 = P2V2/T2. the respond supplies you each and each component yet V2. Givens: 1st (Given) tension - one million.00 atm 1st (Given) temperature - 0C, or 273K 1st (Given) volume - 22.4L 2d (Given) tension - one million.00 atm (it particularly is an identical) 2d (Given) temperature - 90C, or 363K Unknowns: 2d volume How we locate V2 is by potential of utilising manipulating the preliminary equation suggested on the main suitable of the located up. What you get is P1V1T2/T1P2 = V2. Now in basic terms plug in you givens and freshen up! choose this helped :)