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# Determine the stoichiometric air/fuel ratio by mass for the combustion of Heptane (C7H16).?

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- DavidLv 41 decade agoFavorite Answer
Start with your reaction balance equation:

a(C7H16) + b(O2 + 3.76 N2) → c(CO2) + d(H2O) +b(3.76 N2)

Balancing the equation gives you:

a = 1

b = 11

c = 7

d = 8

So, in order to have complete combustion, you need 15 mols of air for every mole of C7H16.

To convert this to a mass basis, you need to know how many kg are in each kmol.

1kmol C7H16 = 7(12)+16(1) kg = 100 kg

1kmol air = 2(16)+3.76*2*(14) = 137.28 kg

Since you need 11 kmol of air for each kmol of C7H16, your air/fuel ratio is:

11(137.28)/100 = 15.1

Source(s): Mechanical Engineer- Login to reply the answers

- arnerichLv 43 years ago
Stoichiometric Air Fuel Ratio

Source(s): https://shrinke.im/a0nLc- Login to reply the answers

- 1 decade ago
check out this article on Wikipedia. There are formulas at the bottom that may help you out.

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