Determine the stoichiometric air/fuel ratio by mass for the combustion of Heptane (C7H16).?

4 Answers

  • David
    Lv 4
    1 decade ago
    Favorite Answer

    Start with your reaction balance equation:

    a(C7H16) + b(O2 + 3.76 N2) → c(CO2) + d(H2O) +b(3.76 N2)

    Balancing the equation gives you:

    a = 1

    b = 11

    c = 7

    d = 8

    So, in order to have complete combustion, you need 15 mols of air for every mole of C7H16.

    To convert this to a mass basis, you need to know how many kg are in each kmol.

    1kmol C7H16 = 7(12)+16(1) kg = 100 kg

    1kmol air = 2(16)+3.76*2*(14) = 137.28 kg

    Since you need 11 kmol of air for each kmol of C7H16, your air/fuel ratio is:

    11(137.28)/100 = 15.1

    Source(s): Mechanical Engineer
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  • 3 years ago

    Stoichiometric Air Fuel Ratio

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  • 1 decade ago

    check out this article on Wikipedia. There are formulas at the bottom that may help you out.

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  • 1 decade ago

    Easy -- "apple".

    Source(s): Common sense.
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