Maths - series question? Can anyone help?
if we have two functions
f(x) = ln(3 + x)
g(x) = ln(1+x)
and by using ln(3+x) = ln3 + ln(1 + x/3),
we can show that ln(3 + x) = ln3 + x/3 - x^2/18 + x^3/27
given that you can write 1 + x = 3 + (x -2), and using the answer for the above question,
find the taylor series about 2 for g. Give the first three terms
- Awms ALv 71 decade agoFavorite Answer
Okay... you just need to follow directions here...
ln(3 + x) = ln3 + x/3 - x^2/18 + x^3/27
g(x) = ln(3 + (x-2) ) = the same as above, but with x replaced with (x-2).