Magnetic flux question?
A 200 turn coil has a 15.2 V potential difference induced in it when the magnetic field changes from 0.42 T to 0.22 T in the opposite direction in 3.2 x 10^2 s. What is the radius of the coil?
so i did:
E=-N delta phi/delta time
and came out with 121.6 for A.
then i did:
and got 6.22 but its wrong.
the real answer is 3.5 x10^2.
any help on this is much appreciated.
- JacyLv 71 decade agoFavorite Answer
Employ Faradays’ law of induction:
emf = dΦ/dt,
where: Φ = NBA
therefore: emf = NAdB/dt,
where: dB/dt = [0.42 – (-0.22)]/(3.2x10-²)
= 0.64/3.2 x 10-² = 0.2 x 10² T/s
Emf = 15.2 = 200(πr²)(0.2x10²),
r = √ [15.2x10-²/(40π) = 3.5x10-² m
Note: I had to make a correction in the time the magnetic
field changes, I believe it should be changing in
a more realistic 3.2x10-² s and not 3.2x10² sec. as
you specified in your question.
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