How do you graph this function?
x = y^2 - 4y + 5
Preferably utilizing 'completing the square' method. Thanks.
Also does anyone know an online program/download that can graph functions of the form x = f(y)?
Also what is the vertex and what are the relevant intercepts.
- NEWLv 41 decade agoFavorite Answer
x = y^2 - 4 y + 5
x= y^2 - 4 y + 2 + 3
x = ( y - 2 ) ^2 + 3
Now to graph it let's do the following
Replace all x's with y's and y's to x's
y = (x-2)^2 + 3
Now you can graph each part:
first you should know how to graph y = x, draw it and consider it fun1
Then x - 2 means you shift fun 1 to the right by two steps gives u fun2
Then (x-2)^2 means you multiply each point you got from fun 2 by itself
which gives you positive points only (above the x axis) .. call it fun3 Shift the entire graph (fun3) up by three steps ... gives you fun4
Now fun4 is the graph of y = (x-2)^2 + 3
now to go back to x = y^2 - 4y + 5 you need to do the inverse graph
Inverse graph is the mirror of the function around angle 45
In other words, draw a line starting from 0,0 and extend it to make 45 degree with the x- axis and consider it as a mirror to fun 4 , the result will be you final graph for x = y^2 - 4y + 5
This link about inverse graph http://www.purplemath.com/modules/invrsfcn.htm
You can also use this link to graph regular functions then you have to inverse it by urself
Sorry I couldn't find any inverse function graph er ;(
- 1 decade ago
Imagine that the position of x and y is reversed, graph that and then turn your head 90 degrees. This is the easiest and most succinct way, there's no reason for anything more complicated.