Hard problem on geometry Help!?

http://www.scriblink.com/index.jsp?act=phome&ld=1&...

Question and everything you need at this link to solve it.

Please explain in very detail and how you proved everything.

Update:

FIND PART B) REMEMBER TO GIVE RATIOS except 1:1 or 25:9 and 9:25

2 Answers

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  • Andy J
    Lv 7
    1 decade ago
    Favorite Answer

    And because the triangles are similar and have ratio of areas of 9:25, their corresponding sides have ratio √9 : √25 or 3:5. Thus:

    AG / CG = 3/5

    AG / 10 = 3/5

    AG = 6

    Likewise:

    GB / GE = 3/5

    GB / 15 = 3/5

    GB = 9

    Again, because of similarity between triangles AGF and CGB:

    GB / GF = CG / AG

    I think you can figure it from here...

  • 1 decade ago

    The actual unreduced area ratio for AGB : GCE is 27/75

    BG/EG = GA/GC

    x/15 = y/10

    y = 10x/15

    The area of triangle of AGB is 27, then (1/2)*10x^2/15 = 27

    x = GB = 9 and y = AG = 6

    For triangle AGF you do the same, the sides AG and EG are congruent, so are GF and GC

    AG/EG = GF/GC

    GF = 10*AG/15 = 4

    FE = 15 - 4 = 11

    This isn't really relevant but if you look at the drawing there's one angle indicated that is perpendicular this means that all the adjacent angles next to it are 90.

    I will pick the triangles AGF and ACB giving 12/27 = 4/9

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