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# If x^2-10x+C is a perfect square trinomial, what is the value of C?

Then, write the trinomial in factored form , i.e, as a square binomial.

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- seed of eternityLv 61 decade agoBest Answer
C should be the half of B squared

(10/2)^2 = 25

Source(s): For assistance related to quadratic equation: http://orimath.com/product/qsolver.php - Anonymous1 decade ago
25

- Anonymous1 decade ago
C = (-10/2)² = 25

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- 1 decade ago
Since the formula would be:

(a+b)(a+b) = a^2 + 2ab + b^2

Take the middle factor (2ab): -10x

Divide it by the "a": -10x/x

Which leaves us with 2b: -10

Divide it by 2 to find the "b": -10/2

So b is: -5

Square this to get the b^2, or C in your case: 25

And it's as simple as that :]

So...

(x-5)(x-5) = x^2 -10x + 25

Source(s): loooots of math classes x.x - 1 decade ago
C=25

(x-5)^2

It's x-5 as opposed to x+5 because in the original equations it is -10x instead of +10x

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