need help working problem, solve sqrt(1-3x)-1=x?

sqrt(1-3x)-1=x

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• Anonymous

√(1 - 3x) - 1 = x

==> √(1 - 3x) = x + 1

==> [√(1 - 3x)]^2 = (x + 1)^2

(Extraneous solution may result. Previous sign condition lost.)

==> -3x + 1 = x^2 + 2x + 1

==> 0 = x^2 + 5x

==> x(x + 5) = 0

==> x = 0 and x = -5

Check:

-> x = 0 <-

√[1 - 3(0)] - 1 = 0

==> √(1 - 0) - 1 = 0

==> 1 - 1 = 0

==> 0 = 0

-> x = -5 <-

√[1 - 3(-5)] - 1 = -5

==> √16 - 1 = -5

==> 4 - 1 = -5

==> 3 ≠ -5

Therefore, x = -5 must be discarded. The only solution is x = 0.

• buvens
Lv 4
4 years ago

section a million #a million 3x - y = 9 #2 2x + 2y = 14 Multiply 2 on equation #a million then upload the two equation 6x - 2y = 18 + 2x + 2y = 14 --------------------- 8x + 0 = 32 x = 4 replace 4 for x into equation #a million (or #2) 3(4) - y = 9 y = 3 So, x = 4 , y = 3 section 2 0.4x + 3y = 2.6 x - 2y = 4.6 Equations are in decimal element so we would desire to remodel it into integers. Multiply 10 on each equation #a million 4x + 30y = 26 #2 10x - 20y = 40 six Multiply 2 on #a million and 3 on #2 and then upload. 8x + 60y = fifty two + 30x - 60y = 138 ----------------------- 38x + 0 = one hundred ninety x = 5 replace 5 for x into #a million 4(5) + 30y = 26 y = a million/5 = 0.2 So, x = 5, y = 0.2 There you bypass! have exciting fixing!

Sqrt(1-3x)-1=x

Sqrt(1-3x)=x+1

square both sides

1-3x=x^2+2x+1

x^2+5x=0

x(x+5)=0

x={0,-5}

need ur points. Choose as d best.