Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 decade ago

# chem hw help please? thank you!!!?

Phosgene, COCl2, used in the manufacture of polyurethane plastics, is prepared from CO & Cl2.

CO(g) + Cl2(g) <---> COCl2(g)

An equilibrium mixture at 395 degrees C contains 0.0102 mol CO & 0.025 mol Cl2 per liter, as well as COCl2. If Kc at 395 degrees C is 1.23 x 10^3, what is the concentration of COCl2?

thankss/ !!

Relevance
• Dr.A
Lv 7

Kc = 1.23 x 10^3 = [COCl2]/ 0.0102 x 0.025

[COCl2]= 0.314 M

• 1 decade ago

Well, Kc is the equilibrium constant. The equation for this is:

Kc=concentration of products/concentration of reactants

so you plug the info in...

1.23x10^3 = COCl2/.0102 x .025

cross multiply...

COCl2 = .31365 mol/L

And that's it.

• ?
Lv 4
3 years ago

whilst multiplying with important figures, we use the kind of digits from the least precise sort. notwithstanding, because of the fact the difficulty states that there are precisely 60 seconds in a minute, that turns right into a definition, no longer a length, so we don't could desire to agonize with regard to the kind of sig. dig. an identical is authentic for the kind of minutes in an hour and the kind of hours in an afternoon. notwithstanding, 365.24 is a rounded sort, so we would use the kind of sig. dig in that kind for our answer. because of the fact that 365.24 has 5 sig. dig., the respond could have 5 sig. dig., so 3.1557 x 10^7.