chem hw help please? thank you!!!?
Phosgene, COCl2, used in the manufacture of polyurethane plastics, is prepared from CO & Cl2.
CO(g) + Cl2(g) <---> COCl2(g)
An equilibrium mixture at 395 degrees C contains 0.0102 mol CO & 0.025 mol Cl2 per liter, as well as COCl2. If Kc at 395 degrees C is 1.23 x 10^3, what is the concentration of COCl2?
- Dr.ALv 71 decade agoFavorite Answer
Kc = 1.23 x 10^3 = [COCl2]/ 0.0102 x 0.025
[COCl2]= 0.314 M
- 1 decade ago
Well, Kc is the equilibrium constant. The equation for this is:
Kc=concentration of products/concentration of reactants
so you plug the info in...
1.23x10^3 = COCl2/.0102 x .025
COCl2 = .31365 mol/L
And that's it.
- ?Lv 43 years ago
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- Anonymous1 decade ago
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