Simplify -x3 + 3x2 + 4 + (x2 - 5x - 1).?

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-x3 + 3x2 + 4 + (x2 - 5x - 1).?
= -x^3 + 3x^2 + 4 + x^2 - 5x -1
= -x^3 + 4x^2 - 5x +3

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  • Conner J. answered 5 years ago
    -x3 + 3x2 + 4 + (x2 - 5x - 1)

    I'm assuming that the numbers after the letters are exponents
    ...3......2.........2
    -x +3x +4+(x -5x-1)

    you can remove the () when there is a + before it
    ...3.....2.......2
    -x +3x +4+x -5x-1

    ..............................2..........
    you can add the x to the 3x
    ...3......2
    -x +4x +4-5x-1

    you can add the 4 and the -1
    ...3....2
    -x +4x +3-5x
    The equation above would be a Jr. High answer



    Assuming that this equation is equal to 0 you can find the value of x.
    ...3....2
    -x +4x +3-5x=0

    rearrange the equation so it's easier to work with
    ...3......2
    -x +4x -5x+3=0

    divide the first 3 values by x
    ......2
    x(-x +4x-5)+3=0

    Up to this point I am a little rusty so I'm not sure how to finish it, but I know it is possible. First try to make a binomial, but if that doesn't work you will have to use the quadratic equation.

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    Straight A math student
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  • pioneers answered 5 years ago
    -x3 + 3x2 + 4 + (x2 - 5x - 1)
    = -x^3 + 4x^2 - 5x +3
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  • Pamela answered 5 years ago
    - x^3 + 3x^2 + 4 + x^2 - 5x - 1

    Combine like terms

    - x^3 + 4x^2 + 3
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  • StanS answered 5 years ago
    -x³ + 3x² + 4 + (x² - 5x - 1)
    -x³ + 3x² + 4 + x² - 5x - 1
    -x³ + 4x² - 5x + 3
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  • Harry > Edward answered 5 years ago
    -x^3 + 4x^2 - 5x + 3
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  • Stranger answered 5 years ago
    I'm doing the samthing in 7th grade math.....

    -16x + 4
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