Other Answers (6)
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x3 + 3x2 + 4 + (x2  5x  1)
I'm assuming that the numbers after the letters are exponents
...3......2.........2
x +3x +4+(x 5x1)
you can remove the () when there is a + before it
...3.....2.......2
x +3x +4+x 5x1
..............................2..........
you can add the x to the 3x
...3......2
x +4x +45x1
you can add the 4 and the 1
...3....2
x +4x +35x
The equation above would be a Jr. High answer
Assuming that this equation is equal to 0 you can find the value of x.
...3....2
x +4x +35x=0
rearrange the equation so it's easier to work with
...3......2
x +4x 5x+3=0
divide the first 3 values by x
......2
x(x +4x5)+3=0
Up to this point I am a little rusty so I'm not sure how to finish it, but I know it is possible. First try to make a binomial, but if that doesn't work you will have to use the quadratic equation.Source(s):
Straight A math student 
x3 + 3x2 + 4 + (x2  5x  1)
= x^3 + 4x^2  5x +3 
 x^3 + 3x^2 + 4 + x^2  5x  1
Combine like terms
 x^3 + 4x^2 + 3 
x³ + 3x² + 4 + (x²  5x  1)
x³ + 3x² + 4 + x²  5x  1
x³ + 4x²  5x + 3 
x^3 + 4x^2  5x + 3

I'm doing the samthing in 7th grade math.....
16x + 4
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