Determine whether the graphs pf the twp equations are perpendicular.?

y=9x-2

6y=5-x

are the graphs of the given equations perpendicular?

4 Answers

Relevance
  • 1 decade ago
    Favorite Answer

    In order to know whether the two lines are in perpendicular, you need to focus on their gradient.

    Let m1 be the gradient of linear equation 1, y=(m1)x+c

    and m2 be the gradient of liners equation 2, y=(m2)x+c

    then if m1 times m2 equal to -1, then the two lines are perpendicular.

    For example, if m1 is 2, then m2 need to be (-1/2) in order to form perpendicular with line 1.

    So, take your question as an example.

    Write both of them in the form of y=mx+c

    Linear Equation 1 : y=9x-2 ; hence, m1=9

    Linear Equation 2 : 6y=5-x

    y=(-1/6)x+(5/6) ; hence m2=(-1/6)

    Since m1*m2 is not equal to -1, [ which is 9*(-1/6)=(-3/2) ],

    so, the two liners equation given are not in perpendicular.

  • 1 decade ago

    Perpendicular means the slopes are opposite reciprocals. You need to find the slope of each line to see

    y = 9x - 2 m = 9/1

    y = (-1/6)x + 5/6 m = -1/6

    NOT perpendicular! the slope of the second line wouldn't needed to be m = -1/9

  • krug
    Lv 4
    3 years ago

    To be perpendicular, the slopes must be the unfavourable reciprocal 5x -2y = 7, 5y - 2x = 3 2y=5x-7 or y = 5/2 x-7/2 5y = 2x+3 or y =2/5 x+3/5 is reciprocal yet no longer unfavourable, so no is the respond

  • Not perpendicular.

    Because m1m2 does not equal to -1

Still have questions? Get your answers by asking now.