complete the proof? it is really hard?
Converse of the Perpendicular Bisector Theorem: Any point equidistant from the endpoints of the segment lies on the perpendicular bisector of the segment.
Given: AD = BD
AE = BE
Prove: DE is the perpendicular bisector of AB
1. AD = BD
AE = BE
2. DE = DE
3. triangle ADE @ triangle BDE
4. Angle AED is congruent to Angle BED
5. CE is congruent to CE
6. AEC is cong. to BEC
7. Angle ACE is cong. to BCE
8. Angle ACE and Angle BCE linear pair
9. Angle ACE plus Angle BCE =180
10. AB is perp. to DE Angle ACE =90 Angle BCE = 90
11.AC is cong. to BC
12. Angle ACE and BCE right angles
13. AB is perp. to DE
14. C is the midpoint of AB
15. DE is perp. bisector
I need all the reasons
- Anonymous1 decade agoFavorite Answer
You have to show us the diagram first...be fair!