Determine the speed of the Hubble telescope when it is in orbit 598 km abouve the earths surface?

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  • 1 decade ago
    Best Answer

    To solve this question you need to use this equation:

    F(gravity)= (Gm1m2)/r²

    (Gm1m2)/r² = m2a(centripetal)

    the m2's cancel and centripetal acceleration equals v^2/r

    (Gm1/r^2) = v^2/r

    (Gm1/r) = v^2

    v=√(Gm1/r)

    v=√(6.67 x 10^-11)((6.0 x 10^24)/(1))((1)/(6.9 x 10^6))

    v=7.6 x 10^3 m/s

    Hope this helped :)

  • 3 years ago

    Hubble Telescope Speed

  • Anonymous
    1 decade ago

    if the Hubble is in Geo-Synchronous Orbit, shouldnt it be going the same speed as the planet's rotation?

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