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# Determine the speed of the Hubble telescope when it is in orbit 598 km abouve the earths surface?

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- 1 decade agoFavorite Answer
To solve this question you need to use this equation:

F(gravity)= (Gm1m2)/r²

(Gm1m2)/r² = m2a(centripetal)

the m2's cancel and centripetal acceleration equals v^2/r

(Gm1/r^2) = v^2/r

(Gm1/r) = v^2

v=√(Gm1/r)

v=√(6.67 x 10^-11)((6.0 x 10^24)/(1))((1)/(6.9 x 10^6))

v=7.6 x 10^3 m/s

Hope this helped :)

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- patchellLv 43 years ago
Hubble Telescope Speed

Source(s): https://shrinkurl.im/a76N6- Login to reply the answers

- Anonymous1 decade ago
if the Hubble is in Geo-Synchronous Orbit, shouldnt it be going the same speed as the planet's rotation?

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