Determine the speed of the Hubble telescope when it is in orbit 598 km abouve the earths surface?
- 1 decade agoFavorite Answer
To solve this question you need to use this equation:
(Gm1m2)/r² = m2a(centripetal)
the m2's cancel and centripetal acceleration equals v^2/r
(Gm1/r^2) = v^2/r
(Gm1/r) = v^2
v=√(6.67 x 10^-11)((6.0 x 10^24)/(1))((1)/(6.9 x 10^6))
v=7.6 x 10^3 m/s
Hope this helped :)
- Anonymous1 decade ago
if the Hubble is in Geo-Synchronous Orbit, shouldnt it be going the same speed as the planet's rotation?