# If 113 is a prime number, how would you factor x^2+2x-113=0?

One of my algebra assignments was to find two consecutive integers such that the sum of their square is 113. I made the equation x(x+2)=113 and distributed, and got x^2+2x=113. Then I subtracted 113 from each side to get the Zero-Product property. But now, the only factors of 113 is 113 x 1, and that doesn't...
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One of my algebra assignments was to find two consecutive integers such that the sum of their square is 113. I made the equation x(x+2)=113 and distributed, and got x^2+2x=113. Then I subtracted 113 from each side to get the Zero-Product property. But now, the only factors of 113 is 113 x 1, and that doesn't add up to be 2. Please help! What am I doing wrong?

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