Anonymous
Anonymous asked in Yahoo ProductsYahoo Answers · 1 decade ago

BLOCKED OR NOT? A mate of mine said he´d been blocked by a girl but he DID answer her other question. How´s it?

Does Yahoo!Answers fulfill the norms, follow its own rules, or...? They say a blocked user can see NOTHING of the blocker NOR contact him/her.

How can we know whether we´ll be respected or not here other way?

Update:

Hi! Shy, I don´t know what you´d do with 2 more points. Anyway I meant that person used his previous name and answered as usually, with no subterfuge; so he was blocked like "just formally" but not "really instead". I just wonder how she then felt, just ignored as a user, as a person!!!

3 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    Respondendo a pergunta:Vc entra deslogado na pergunta e se loga assim que for responder.Mas continua não podendo enviar email(caso a pessoa aceite) e não poderá se tornar "amigo" da mesma tbm.

    Quanto à outra pergunta(aquela do restaurant no YR Brasil)...

    Quer matar a perguntona de ódio?Me elogie!Ela,por alguma razão absolutamente desconhecida por mim,me detesta,me negativa,compete comigo como se isto fosse um jogo por pontos e inveja minha pobre faixinha laranja de top.PORÉM,copia muitas vezes minhas respostas!Vai entender a alma humana!E não me coloque com ela no "restaurant"...perco a fome!rsrs

    Não sou chiqérrima.Sou muito delicada no trato.

    Seria vc o Petbull edição maio de 2009?

    Bom dia.

  • ?
    Lv 7
    1 decade ago

    you know what i was and still am blocked by another girl, but you know what i still answered her question despite her blocking me.

    what i did, was log off, type in the address of the question on my browser, it went to the question and the blue sign saying "answer question" was there, i clicked on it and logged back on then answered, and i was awarded 2 points

  • 1 decade ago

    Hi,

    i came accross you know french.

    do you think you can answer my question?

    http://answers.yahoo.com/question/index;_ylt=AgG0B...

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