ZZZ asked in 科學數學 · 1 decade ago

一題三角函數的問題 幫個忙

根號3 sin92度 - cos92度 等於多少?

請要給計算方法噢 謝謝

Update:

linch 請問是怎麼算的ㄚ?

QQ 你怎麼不直接回答呢~

4 Answers

Rating
  • 1 decade ago
    Favorite Answer

    √3sin92-cos92

    =2((√3/2)sin92-(1/2)cos92)

    =2((cos30)sin92-(sin(30 )cos92)

    =2(sin(92-30) )

    =2(sin(62 ))

    我來檢便宜好了

    補個類似題:

    csc10 −√3sec10=?

    (1/sin10 )−√3(1/cos10 )= (cos10 −√3sin10 )/(sin10 cos10 )

    =2((1/2)cos10 −(√3/2)sin10 )/((1/2)sin20 )

    =2(sin30 cos10 −cos30 sin10 )/((1/2)sin20 )

    =2sin20 /((1/2)sin20 )=4

  • rex
    Lv 7
    1 decade ago

    我也同時刪了

    因為看到螞蟻雄兵的解答了 ><" 

  • 1 decade ago

    √3sin92°-cos92°等於多少?

    =2((√3/2)sin92°-(1/2)cos92°)

    =2((cos30°)sin92°-(sin(30°)cos92°)

    =2(sin(92-30)°)

    =2(sin(62°))

    2009-04-01 01:39:53 補充:

    ""><"""

  • linch
    Lv 7
    1 decade ago

    2 sin 62

    2009-03-31 22:31:26 補充:

    給新人一些機會

    另外你也沒寫清楚你到底要的是甚麼?

    化簡?? 值??

    所以我就簡單寫囉

    2009-03-31 23:40:40 補充:

    疑?雄兵大大怎麼把答案刪了呢?

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