Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

Finding the angle that maximizes the projectile's range?

The range of a projectile is R=(vsin(2theta))/g

v is initial velocity

g is acceleration due to gravity and is constant

theta is the firing angle

This is in the section of optimization for calculus which means i need another equation besides the one given, but I don't know what the other equation would be.

And just saying maximizing sin(2theta) won't work, it needs to be an equation.

Thanks!

2 Answers

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  • 1 decade ago
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    Find the deivative of the range and set to 0

    R'=(2v/g)cos(2theta)=0

    cos(90 degrees)=0

    cos(-90)=0

    90=2 theta so theta=45 degrees

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  • 1 decade ago

    2v/g(cos 2θ) = 0 ?

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