how many mLs of a .5 M NaOH solution will be required to titrate 1.2 g of KHP to the Phenolphthalein endpoint?

how many mLs of a .5 M NaOH solution will be required to titrate 1.2 g of KHP to the Phenolphthalein endpoint?

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  • 1 decade ago
    Favorite Answer

    Use the titration formula for quickest results

    ml NaOH required = (1000 X 1.2 gKHP)/(0.5M X molar mass of KHP) the molar Mass of KHP = 204 .23

    ml = 1000 X 1.2 /0.5 x 204.23 = 11.75 mls NaOH

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  • Erika
    Lv 4
    3 years ago

    i'm going to assume the difficulty is inquiring for the concentration of the NaOH answer. KHP is the abbreviation for KHC8H4O2 and its molar mass is 204.24 g/mol. NaOH + KHP -----> NaKP + H2O one million mol NaOH reacts with one million mol KHP 0.775 g KHP x (one million mol KHP / 204.24 g) = 0.00379 mol KHP = 0.00379 mol NaOH (one million:l) M = mol / L = 0.00379 mol NaOH / 0.03511 L = 0.108 M (3 sig figs)

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