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# how many mLs of a .5 M NaOH solution will be required to titrate 1.2 g of KHP to the Phenolphthalein endpoint?

how many mLs of a .5 M NaOH solution will be required to titrate 1.2 g of KHP to the Phenolphthalein endpoint?

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- Doc89891Lv 71 decade agoFavorite Answer
Use the titration formula for quickest results

ml NaOH required = (1000 X 1.2 gKHP)/(0.5M X molar mass of KHP) the molar Mass of KHP = 204 .23

ml = 1000 X 1.2 /0.5 x 204.23 = 11.75 mls NaOH

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- ErikaLv 43 years ago
i'm going to assume the difficulty is inquiring for the concentration of the NaOH answer. KHP is the abbreviation for KHC8H4O2 and its molar mass is 204.24 g/mol. NaOH + KHP -----> NaKP + H2O one million mol NaOH reacts with one million mol KHP 0.775 g KHP x (one million mol KHP / 204.24 g) = 0.00379 mol KHP = 0.00379 mol NaOH (one million:l) M = mol / L = 0.00379 mol NaOH / 0.03511 L = 0.108 M (3 sig figs)

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