What are the answers to these Chemistry questions?

I can not find the answers to these questions can you help me please?

1)Which element when combined with chlorine would most likely form an ionic compound?

2)What is the first element in the formula of every ionic compound?

3)How many atoms are in Tin (IV) hydroxide, Sn(OH)4?

3 Answers

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  • 1 decade ago
    Favorite Answer

    1. Compounds with a high ionic character have the highest electronegativity differences. Therefore, metals in group IA and chlorine will produce very ionic-like bonds. Keep in mind, though, that there are no 100% ionic bonds in solids. Even the most ionic of bonds, Cs-F, is 92 period ionic (8 percent covalent), and NaCl is about 70% percent ionic.

    2. Again, there are no 100% ionic compounds. Only compounds that are very polar and bond in some kind of network arrangement. It is these that are "ionic-like". In a formula for this kind of compound, the first element would be a metal with a low electronegativity, usually a group IA metal.

    3. Sn(OH)4. You're looking for the atom count? Then count the atoms. It can't be that hard. 1 Sn, 4 O, 4 H. Looks like 9 atoms in one molecule of Sn(OH)4. And yes, Sn(OH)4 is molecular. It is not ionic.

  • BP
    Lv 7
    1 decade ago

    1)Which element when combined with chlorine would most likely form an ionic compound? Sodium (Na), or anything in the first column of the periodic table.

    2)What is the first element in the formula of every ionic compound? A metal, which is the cation of the compound.

    3)How many atoms are in Tin (IV) hydroxide, Sn(OH)4?

    nine

    Source(s): bp
  • Kaye d
    Lv 4
    1 decade ago

    1) Na would form NaCl

    2) cation (the ion of positive charge)

    3) 9 atoms: 1 Sn, 4 O, 4 H

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