### Other Answers (6)

Relevance-
First add 20 to both sides, so the equation reads x^2 - 9x + 20 = 0. Since this is a quadratic, you expect to be able to factor it into (x+a)(x+b) = 0. You're trying to find a and b so that a + b = -9 and ab = 20. From looking at it and trying different numbers, you should get -4 and -5. (-4 + -5 = -9 and -4 * -5 = 20). So the factorization is (x-4)(x-5) = 0.

Now the only way for a product of two factors to equal zero is for one or both of them to be zero. That is, x-4 = 0 or x-5 = 0. If you solve these equations, you get x=4, x=5 as solutions. -
Transpose -20:

x2 - 9x + 20 = 0; from here you can factor out.

(x - 5)(x - 4) = 0; set both factors to zero.

x - 5 = 0 ; x - 4 = 0

Therefore the two roots are: x = 5 and x = 4. -
Get all numbers on 1 side and make the equation = 0:

x2-9x+20

Then factor everything out like normal:

(x-4)(x-5)

If you want to solve for x, all you have to do is make one parenthesized equation 0 so you would either have 4 as x or 5 as x

x=4 or 5 to make the equation 0 Plug it in! -
x^2 - 9x + 20 = 0

(x - 4) * (x - 5) -
x^2-9x=-20

x^2-9x+20=0

Factor:

(x-4)(x-5) -
factor x^2-2x-15