# equation line slope????? help!!!!!!!!!!!!?

Write the equation of a line in slope-intercept form with the slope of 4/5 and y-intercept (0, -5).

Relevance

First you must find the y intercept, which is found by setting your x co-ordinate to zero in the equation. This equation already has x as a zero, so your y intercept is (0, -5). Now you must find the slope, or (m). m is given to you as 4/5, so m=4/5. At this point you simply need to make it slope-intercept form, where the coefficient of x is the slope, and the y intercept is the number added ( or subtracted ) to/from it. That is to say, (y = mx + b). Now all you need to do is plug in your y co-ordinate at the intercept at b and your slope at m. (x and y are your variables, so you don't need to worry about them).

(y = 4/5 - 5) is the answer

I hope I have clearly explained how to express an equation in slope intercept form.

• slope intercept form is y -mx+b, where M is the slope, and B is the y intercept. So Your equation would be Y = 4/5X - 5 :]

• you take the m which is slope and the b which is y intercept and put them in slope intercept form y= m(x) + b so that would be y = 4/5(x) - 5

• general form: y=mx +b where m is the slope and b is the y intercept; so

y= 4/5x -5

• Anonymous

Slope intercept for is: y = mx + b

Since you have all the values except b you can fill in and solve for b.

y = mx + b

-5 = (4/5)(0) + b

-5 = 0 + b

b = -5

So, y = (4/5)x - 5

• Anonymous

The equation of a line is y = mx+b

m = slope

b = y-intercept

Just plug in your values and there you go. =]

• y=mx+b

m = 4/5

y=(4/5)x+b

at (0,-5)

b = -5

y = (4/5)x - 5

• Anonymous