Please help with math?

Peter sold pumpkins from his farm. He sold jumbo pumpkins for $9.00 each, and he sold regular pumpkins for $4.00 each. Peter sold 80 pumpkins and collected $395.00. How many jumbo pumpkins and regular pumpkins did he sell?

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Update:

Thanks for letting me do the like adding stuff KYLE M u get 10pts

THANK YOU COMEAGAIN

6 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    Let Jumbo = X amount

    Let Reg. = Y amount

    9X + 4Y = 395

    X + Y = 80

    multiply bottom by 4, subtract the 2 equations

    9X + 4Y = 395

    4X + 4Y = 320

    so 5X = 75, so X = 15

    if X is 15, Y must be 65

    so he sold 15 jumbo, and 65 regular

  • 1 decade ago

    Let x = number of jumbo pumpkins sold

    80 - x = number of regular pumpkins sold

    9.00(x) + 4.00(80 - x) = 395.00

    9.00x + 320.00 - 4.00x = 395.00

    9.00x - 4.00x = 395.00 - 320.00

    5.00x = 75.00

    x = 75.00/5.00 = 15 jumbo pumpkins sold

    80 - 15 = 65 regular pumpkins sold

  • Kyle M
    Lv 6
    1 decade ago

    j = # jumbo

    r = # regular

    80 = j + r

    $395.00 = 9j + 4r ~~~ (solve for one of these variables)

    j = 80 - r (from first equation) (plug into second)

    395= 9(80-r) + 4r (simplify)

    395 = 720 - 9r + 4r

    395 = 720 - 5r (solve for r)

    -325 = -5r

    r = 65

    (now put r into the first equation and solve for j)

    80 = j + 65

    j = 15

    So 15 jumbo pumpkins and 65 regular pumpkins.

  • 1 decade ago

    9x + 4(80 - x) = 395

    9x + 320 - 4x = 395

    5x = 395- 320

    5x = 75

    x = 15 jumbo pumpkins

    80- 15 = 65 regular pumpkins

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  • Anonymous
    1 decade ago

    J-57

    Regular=30

  • 1 decade ago

    9x+4y=395

    x+y=80

    y=-x+80

    9x+4(-x+80)=395

    9x-4x+320=395

    5x=75

    x=15

    15+y=80

    y=65

    Answer: 15 jumbo pumpkins and 65 regular pumpkins

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