Peter sold pumpkins from his farm. He sold jumbo pumpkins for \$9.00 each, and he sold regular pumpkins for \$4.00 each. Peter sold 80 pumpkins and collected \$395.00. How many jumbo pumpkins and regular pumpkins did he sell?

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• Anonymous

Let Jumbo = X amount

Let Reg. = Y amount

9X + 4Y = 395

X + Y = 80

multiply bottom by 4, subtract the 2 equations

9X + 4Y = 395

4X + 4Y = 320

so 5X = 75, so X = 15

if X is 15, Y must be 65

so he sold 15 jumbo, and 65 regular

• Let x = number of jumbo pumpkins sold

80 - x = number of regular pumpkins sold

9.00(x) + 4.00(80 - x) = 395.00

9.00x + 320.00 - 4.00x = 395.00

9.00x - 4.00x = 395.00 - 320.00

5.00x = 75.00

x = 75.00/5.00 = 15 jumbo pumpkins sold

80 - 15 = 65 regular pumpkins sold

• j = # jumbo

r = # regular

80 = j + r

\$395.00 = 9j + 4r ~~~ (solve for one of these variables)

j = 80 - r (from first equation) (plug into second)

395= 9(80-r) + 4r (simplify)

395 = 720 - 9r + 4r

395 = 720 - 5r (solve for r)

-325 = -5r

r = 65

(now put r into the first equation and solve for j)

80 = j + 65

j = 15

So 15 jumbo pumpkins and 65 regular pumpkins.

• 9x + 4(80 - x) = 395

9x + 320 - 4x = 395

5x = 395- 320

5x = 75

x = 15 jumbo pumpkins

80- 15 = 65 regular pumpkins

• Anonymous

J-57

Regular=30

• 9x+4y=395

x+y=80

y=-x+80

9x+4(-x+80)=395

9x-4x+320=395

5x=75

x=15

15+y=80

y=65

Answer: 15 jumbo pumpkins and 65 regular pumpkins