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Reaction enthalpy for the formation of aluminum chloride?
can someone please help me and explain how to get the answer? the first correct answer gets a best answer. thanks a lot!
Calculate the reaction enthalpy for the formation
2 Al(s) + 3 Cl2(g) − → 2 AlCl3(s) ,
of anhydrous aluminum chloride using the data
2 Al(s) + 6 HCl(aq) − → 2 AlCl3(aq) + 3 H2(g) ∆H◦ =...
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can someone please help me and explain how to get the answer? the first correct answer gets a best answer. thanks a lot!
Calculate the reaction enthalpy for the formation
2 Al(s) + 3 Cl2(g) − → 2 AlCl3(s) ,
of anhydrous aluminum chloride using the data
2 Al(s) + 6 HCl(aq) − → 2 AlCl3(aq) + 3 H2(g) ∆H◦ = −1049 kJ
HCl(g) −→ HCl(aq) ∆H◦ = −74.8 kJ
H2 (g) + Cl2 (g) −→ 2 HCl(g) ∆H◦ = −185 kJ
AlCl3(s) −→ AlCl3(aq) ∆H◦ = −323 kJ
1. −1450.85 kJ
2. −1826.2 kJ
3. −1502.4 kJ
4. −1883.5 kJ
5. −1225.7 kJ
6. −1100.36 kJ
7. −1406.8 kJ
Calculate the reaction enthalpy for the formation
2 Al(s) + 3 Cl2(g) − → 2 AlCl3(s) ,
of anhydrous aluminum chloride using the data
2 Al(s) + 6 HCl(aq) − → 2 AlCl3(aq) + 3 H2(g) ∆H◦ = −1049 kJ
HCl(g) −→ HCl(aq) ∆H◦ = −74.8 kJ
H2 (g) + Cl2 (g) −→ 2 HCl(g) ∆H◦ = −185 kJ
AlCl3(s) −→ AlCl3(aq) ∆H◦ = −323 kJ
1. −1450.85 kJ
2. −1826.2 kJ
3. −1502.4 kJ
4. −1883.5 kJ
5. −1225.7 kJ
6. −1100.36 kJ
7. −1406.8 kJ
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