Use the elimination method to solve the following system of equations ?

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2x+5y= -22
10x+3y=22
Best Answer
2x+5y= -22
10x+3y=22

multiply both sides of the first equation by -5 and add to the second
that will eliminate x

-10x -25y = 110
10x + 3y = 22
-22y = 132
y = -6

Substituting (-6) for y in either equation:
2x + 5(-6) = -22
2x = 8
x = 4

10x + 3(-6) = 22
10x = 40
x = 4

so the solution to the system is (4,-6)
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  • sreedevi s answered 5 years ago
    Multiply the first equation by 5 and then subtract from second equation.we get 10x + 25y = -110
    - (10x + 3y = 22)

    that is 22y = 88
    that is y = -6

    For x we substiute the value of y in 2x + 5y = -22
    2x - 30 = -22
    2x = -22 + 30 = 8
    x = 4
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  • cidyah answered 5 years ago
    Let us eliminate y
    Multiply equation (1) by -3 and equation (2) by 5
    -6x-15y=66
    50x+15y=110
    Add:
    44x = 176
    x= 176/44 =4
    plug this x into equation (1)
    2(4) + 5y = -22
    8 +5y =-22
    5y =-30
    y =-6

    x=4, y=-6
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  • Jason answered 5 years ago
    Multiply the first equation by 5:
    10x + 25y = -110

    Now subtract the second equation from the first. This eliminates x, leaving you with:
    22y = -132
    y = -6

    Plug that back in to either equation, and you find that x = 4
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  • werrdna answered 5 years ago
    why do you want the answer
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