# Use the elimination method to solve the following system of equations ?

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2x+5y= -22

10x+3y=22

10x+3y=22

Best Answer

2x+5y= -22

10x+3y=22

multiply both sides of the first equation by -5 and add to the second

that will eliminate x

-10x -25y = 110

10x + 3y = 22

-22y = 132

y = -6

Substituting (-6) for y in either equation:

2x + 5(-6) = -22

2x = 8

x = 4

10x + 3(-6) = 22

10x = 40

x = 4

so the solution to the system is (4,-6)

10x+3y=22

multiply both sides of the first equation by -5 and add to the second

that will eliminate x

-10x -25y = 110

10x + 3y = 22

-22y = 132

y = -6

Substituting (-6) for y in either equation:

2x + 5(-6) = -22

2x = 8

x = 4

10x + 3(-6) = 22

10x = 40

x = 4

so the solution to the system is (4,-6)

### Other Answers (4)

Rated Highest-
Multiply the first equation by 5 and then subtract from second equation.we get 10x + 25y = -110

- (10x + 3y = 22)

that is 22y = 88

that is y = -6

For x we substiute the value of y in 2x + 5y = -22

2x - 30 = -22

2x = -22 + 30 = 8

x = 4 -
Let us eliminate y

Multiply equation (1) by -3 and equation (2) by 5

-6x-15y=66

50x+15y=110

Add:

44x = 176

x= 176/44 =4

plug this x into equation (1)

2(4) + 5y = -22

8 +5y =-22

5y =-30

y =-6

x=4, y=-6 -
Multiply the first equation by 5:

10x + 25y = -110

Now subtract the second equation from the first. This eliminates x, leaving you with:

22y = -132

y = -6

Plug that back in to either equation, and you find that x = 4 -
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