Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 decade ago

oxidation in chemistry.3Ag2S(s)+2AL(s)-->6Ag(s)+AL2S3(s)?

a)state the charge(oxidation number) on each ion in each of the compounds listed.

b)identify the oxidized reactant and the reduced reactant.

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  • Dr.A
    Lv 7
    1 decade ago
    Favorite Answer

    3 Ag2S + 2 Al >> 6 Ag + Al2S3

    reactants :

    Ag +1 and S -2

    Al 0

    products

    Ag 0

    Al +3

    S -2

    S spectator ion

    Ag goes from +1 to 0 reduced reactant

    Al goes from 0 to +3 oxidized reactant

  • Anonymous
    4 years ago

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