# Identifing vertex? axis of symmetry? x-intercept?

how can I identify the vertex, axis of symmetry, x-intercepts and writing this equation in standard form???

f(x)= -x^2 + 2x +6

thanks a lot for your help!

### 1 Answer

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- 1 decade agoBest Answer
you need to change it to factored form first. Find what Multipies to -6 and adds to 2. (minus six because you multiply the a value with the c value. Its -1.65 and 3.65. These are your x ints. Now you need to find your x axis by adding your x ints and dividing by two. Xaxis= 1.91 Now sub your x axis into the factored form eqtn to find the y coordinate of your vertex.

y= -1(1.91+1.65)(1.91-3.65)

y=-1(3.56)(-1.74)

y=6.19

Therefore, your xints are -1.65 and 3.65, your Xaxis is 1.91 and your vertex is 6.19

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