The probability that an entering college student will graduate is 0.4. Determine the probability...?
..that out of 6 students a)None will graduate b)One will graduate c)At least one, will graduate d) No more than 5, will graduate e)All will graduate.
- M3Lv 71 decade agoFavorite Answer
this is a problem in binomial probability distribution.
The probability that x students will graduate out of n is given by
P(x) = nCx*p^x*(1-p)^(n-x). Here n = 6 & p = 0.4
a) P(0) = 6C0*(0.4)^0*(0.6)^6 = 4.66%
b) P(1) = 6C1*(0.4)^1*(0.6)^ = 18.66%%
c) P(>=1) = 1 - P(0) = 95.34%
d) P(<=5) = 1 - P(6) = 1 - (0.4)^6 = 95.9%
e) P(6) = 6C6*(0.4)^6*(0.6)^0 = 4.1%
- ?Lv 45 years ago
sounds like this difficulty is getting energetic. For difficulty a million, i'm getting 35/one hundred sixty five or 7/33 %. any specific place on the chain for the 1st pink marble without loss of generality. There at the instant are 9 potential spots to fill in the final 3 pink marbles. exceedingly undemanding to discern 35 plausible mixture with an area between each marble = ( (5+4+3+2+a million) + (4+3+2+a million) + (3+2+a million) + (2+a million) +a million ) = a million/6 ( 5³ + 3 * 5² + 2* 5) = 35 There additionally are 11 diverse spots that the final 3 marbles could desire to be dropped into. This works out to be one hundred sixty five mixture or =a million/6 ( 9³ + 3 * 9² + 2* 9) =one hundred sixty five *********** have not even theory approximately #2 yet ... have been given pass watch the baseball sport and shelter the toddlers. yet i could come back this night if i'm no longer too drained.