find the slope-intercept form of the eqation of the line that passes through(-5,3) and is parallel to 12x-3y=?

=10

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  • Anonymous
    1 decade ago
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    y = 4x + 23

    If the two lines are parallel, then they have the same slope. First, we can change 12x - 3y = 10 to slope-intercept form to determine the slope.

    12x - 3y = 10 (subtract 12x from both sides)

    -3y = -12x + 10 (divide both sides by -3)

    y = 4x - (10/3)

    So, the slope is 4. That means the line that passes through (-5,3) has the form y = 4x + b. We may substitute the x- and y-coordinates from this point for x and y in the equation and solve for b.

    y = 4x + b (substitute y=3, x=-5)

    3 = 4(-5) + b (multiply)

    3 = -20 + b (add 20 to both sides)

    23 = b

    So, the equation of the line you seek is y = 4x + 23.

    I hope this helps!

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