find the exact value of the logarithmic expression.logbase3(72)-3logbase3(2)+ln(5throot of "e" squared)?

if you can understand and slove this question, that would be GREAT. i understand if you can't cuz i know its hard but thanks

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  • Anonymous
    1 decade ago
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    log (base 3) 72-log (base 3) 2^3+ln5√e^2

    log (base 3) 72-log (base 3) 8+ln5√e^2

    log (base 3) 72-log (base 3) 8=log(72÷8)/log3

    log9/log3=2

    8+ln5√e^2=0.4

    2+0.4=2.4

    Therefore:

    log (base 3) 72-log (base 3) 2^3+ln5√e^2=2.4

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